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F (x) = x + 1 and g (x) = x − 1. Web solutions by precalculus with limits (2nd edition) edit edition 81% (58 ratings) for this chapter’s solutions solutions for chapter. Then f ( g ( x ) ) = f ( x − 1 ) = ( x − 1 ) + 1 = x f (.
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Then F ( G ( X ) ) = F ( X − 1 ) = ( X − 1 ) + 1 = X F ( G ( X ).
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